Q. The following are exercise in future
(terminal) values:
a) At the end of three
years, how much is an initial deposit of $100 worth, assuming a compound annual
interest rate of (i) 100 percent? (ii) 0 percent?
b) At the end of five years, how much is an
initial $500 deposit followed by five year-end, annual $100 payments worth,
assuming a compound annual interest rate of (i) 10 percent? (ii) 5 percent?
(iii) 0 percent?
c) At the end of six
years, how much is an initial $500 deposit followed by five year-end, annual
$100 payments worth, assuming a compound annual interest rate of (i) 10
percent? (ii) 5 percent? (iii) 0 percent?
d) At the end of three
years, how much is an initial $100 deposit worth, assuming a quarterly
compounded annual interest rate of (i)
100 percent? (ii) 10 percent?
e) Why your answer to
part (d) is differ from those to part (a)?
f) At the end of 10
years, how much is an initial $100 deposit worth, assuming an annual interest
rate of 10 percent compounded (i) annually? (ii) Semiannually? (iii) Continuously?
Solution:
a)
FVn= P0(1 + i)
(i) FV3= $100(2.0)3 =$100(8)
= $800
(ii) FV3= $100(1.10)3=
$100(1.331)= $133.10
(iii)
FV3= $100(1.0)3= $100(1)
= $100
b)
FVn = P0(1 + i)n; FVAn = R[([1 + i]n - 1)/i]
(i) FV5 = $500(1.10)5 = $500(1.611) = $ 805.50
FVA5 = $100[([1.10]5 - 1)/(.10)]
= $100(6.105) =
610.50
$1,416.00
(ii) FV5 = $500(1.05)5
= $500(1.276) = $ 638.00
FVA5 = $100[([1.05]5 - 1)/(.05)]
= $100(5.526) =
552.60
$1,190.60
(iii) FV5 = $500(1.0)5
= $500(1) = $ 500.00
FVA5 = $100(5)= 500.00
$ 1,000.00
c) FVn= P0(1 + i)n; FVADn= R[([1 + i]n-
1)/i][1 + i]
(i) FV6 = $500(1.10)6 = $500(1.772) = $ 886.50
FVA5 = $100[([1.10]5 - 1)/(.10)]
= $100(6.105) (1.10) = 671.55
$1,557.55
(ii) FV6 = $500(1.05)6
= $500(1.340) = $ 670.00
FVA5 = $100[([1.05]5 - 1)/(.05)]
= $100(5.526) (1.10) = 580.23
$1,250.23
(iii) FV6 = $500(1.0)6
= $500(1) = $ 500.00
FVA5 = $100(5) = 500.00
$ 1,000.00
d) FVn = PV0(1 + [i/m])
(i)
FV3= $100(1 +
[1/4])12 = $100(14.552) = $1,455.20
(ii)
FV3= $100(1 +
[.10/4])12= $100(1.345) = $ 134.50
e)
The more times a year interest is paid, the
greater the future
value.
It is particularly important when the interest rate is
high, as evidenced by the difference in
solutions between
Parts 1.a) (i) and 1.d) (i).
f) FVn= PV0(1 + [i/m])mn; FVn = PV0(e)in
(i)
$100(1 + [.10/1])10 = $100(2.594) = $259.40
(ii)
$100(1 + [.10/2])20 = $100(2.653) = $265.30
(iii)
$100(1 + [.10/4])40= $100(2.685) = $268.50
(iv)
$100(2.71828)1 = $271.83